1988 Virginia Slims of Arizona – Singles

Singles
1988 Virginia Slims of Arizona
1987 Champion	Anne White
Final
Champion	Manuela Maleeva
Runner-up	Dianne Van Rensburg
Score	6–3, 4–6, 6–2
Events
Singles Doubles
← 1987 · Virginia Slims of Arizona · 1989 →

Anne White was the defending champion but lost in the first round to Elly Hakami.

Manuela Maleeva won in the final 6–3, 4–6, 6–2 against Dianne Van Rensburg.

A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated.

	First round							Second round							Quarterfinals							Semifinals							Final
	1	M Maleeva	6	7
		L Antonoplis	1	5				1	M Maleeva	6	6
		M Lindström	6	1	7				M Lindström	4	1
		H Na	4	6	6										1	M Maleeva	6	6
		C Benjamin	1	6	6										8	T Phelps	4	2
	LL	K Keil	6	3	1				C Benjamin	2	2
		A Holíková	0	1				8	T Phelps	6	6
	8	T Phelps	6	6																		1	M Maleeva	6	6
	4	R Fairbank	6	4	6																		E Burgin	1	1
		B Nagelsen	4	6	3			4	R Fairbank	6	2	6
		H Ludloff	3	1					A Grossman	4	6	2
		A Grossman	6	6											4	R Fairbank	5	6	3
	Q	L Allen	6	0	7											E Burgin	7	1	6
		B Herr	2	6	6			Q	L Allen	6	3	4
		E Burgin	6	6					E Burgin	1	6	6
	6	P Louie-Harper	3	3																									1	Manuela Maleeva	6	4	6
	5	D Balestrat	2	6	5																									Dianne Van Rensburg	3	6	2
		W White	6	4	7				W White	6	7
		M L Daniels	1	3					A Ivan	0	5
		A Ivan	6	6												W White	1	2
	Q	R Baranski	3	0												D Van Rensburg	6	6
		D Van Rensburg	6	6					D Van Rensburg	7	6
		M Werdel	5	2				3	N Dias	5	2
	3	N Dias	7	6																			D Van Rensburg	6	6
		A Smith	6	0	1																		S Sloane	2	3
		E Hakami	3	6	6				E Hakami	7	6
	Q	K Steinmetz	7	6				Q	K Steinmetz	6	4
		J Richardson	5	4												E Hakami	2	6	0
		S Sloane	2	6	7											S Sloane	6	4	6
		M Torres	6	4	5				S Sloane	6	1
	Q	M Strandlund	7	6	4			2	P Fendick	0	0	r
	2	P Fendick	6	7	6

• 1988 Virginia Slims of Arizona Draw